(26.8^2)-(26^2)=x^2

Solution for (26.8^2)-(26^2)=x^2 equation:

(26.8^2)-(26^2)=x^2

We move all terms to the left:

(26.8^2)-(26^2)-(x^2)=0

We add all the numbers together, and all the variables

-1x^2+42.24=0

a = -1; b = 0; c = +42.24;
Δ = b2-4ac
Δ = 02-4·(-1)·42.24
Δ = 168.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{168.96}}{2*-1}=\frac{0-\sqrt{168.96}}{-2}
=-\frac{\sqrt{}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{168.96}}{2*-1}=\frac{0+\sqrt{168.96}}{-2}
=\frac{\sqrt{}}{-2}
$